Submission #1687636

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Source Code Expand

#include<iostream>
#include<cstdio>
#include<vector>
#include<map>
#include<tuple>
#include<string>
#include<sstream>
#include<cmath>
#include<climits>
#include<algorithm>
#include<bitset>
#include<set>
#include<stack>
#include<queue>
#include<iomanip>
#include<memory.h>
using namespace std;  
typedef long long ll;
typedef vector<int> vi;
typedef vector<vi> vvi;
#define rep(i,n) for(ll i=0;i<(n);i++)  
#define tii tuple<int,int>
#define tiii tuple<int,int,int>
#define mt make_tuple
#define pb push_back  
#define ALL(a) (a).begin(),(a).end()
#define FST first
#define SEC second  
const int INF = (INT_MAX/2);
const ll LLINF = (LLONG_MAX/2);
const double eps = 1e-5;
const double PI = M_PI;  
#define DEB cerr<<"!"<<endl
#define SHOW(a,b) cerr<<(a)<<" "<<(b)<<endl
#define SHOWARRAY(ar,i,j) REP(a,i)REP(b,j)cerr<<ar[a][b]<<((b==j-1)?((a==i-1)?("\n\n"):("\n")):(" "))
#define DIV int(1e9+7)
inline ll pow(ll x,ll n,ll m){ll r=1;while(n>0){if((n&1)==1)r=r*x%m;x=x*x%m;n>>=1;}return r%m;}
class FermatCombination{
public:
  vector<ll> factrial; // 階乗
  vector<ll> inverse; // 逆元
  FermatCombination(int size){
    factrial.resize(size+1);
    inverse.resize(size+1);
    factrial[0] = 1;
    inverse[0] = 1;
    for(int i = 1; i < size+1; i++){
      factrial[i] = factrial[i-1] * i % DIV;
      inverse[i] = pow(factrial[i],DIV-2,DIV);
    }
  }
  ll combination(int n, int k){
    if(n < k) return 0;
    return factrial[n]* inverse[k] % DIV * inverse[n - k] % DIV;
  }
  ll permutation(int n, int k){
    if(n < k) return 0; 
    return factrial[n] * inverse[n-k] % DIV;
  }
  // 1-nまでの整数から重複を許しn個選ぶパターンの数
  ll multi_choose(int n, int k){
    if(n == 0 && k == 0) return 1;
    else return combination(n+k-1,k);
  }
};

int main(){
  FermatCombination fc(1000);
  int n; cin >> n;
  int l = 0,r = 0;
  map<int,int>  m;
  rep(i,n+1){
    int in; cin >> in;
    if(!r && m[in] != 0){
      r = i+1;
      l = m[in];
      continue;
    }else{
      m[in] = i+1;
    }
  }
  for(int k = 1; k <= n+1; k++){
    ll ans = fc.combination(n+1,k);
    int c = n-r+l;
    ans -= fc.combination(c,k-1);
    ans += DIV;
    cout << ans%DIV << endl;
  }
  
  return 0;
}

Submission Info

Judge Result